Question

A 6 kg weight is lifted off the ground to a height that gives it 70.56 j of gravitational potential energy. what is its height? acceleration due to gravity is g = 9.8 m/s2.

Answer 1

GPE= 70.56 J -------------------> GPE= mgh-------------> X= height
70.56 = 6(kg) * 9.8(m/s/s) * X
70.56 = 58.8X
70.56/58.8= 58.8X/58.8
X= 1.2
The height is 1.2 feet or meters (whatever unit you are using in this problem)

Answer 2

Height, h = 1.2 meters

Step-by-step explanation:

It is given that,

Mass of an object, m = 6 kg

Gravitational potential energy, E = 70.56 J

It is lifted off a ground to a height h. We need to find its height. It can be determined using the expression for the potential energy i.e.

E = m g h

g = acceleration due to gravity

`h=(E)/(mg)`

`h=(70.56\ J)/(6\ kg* 9.8\ m/s^2)`

h = 1.2 meters

Hence, it is lifted off the ground to a height of 1.2 meters.