Question

A 9 v battery causes a current of 0.45 a through a resistor. (a) what is its resistance? (b) how many joules of energy does the battery lose in a minute? j

Answer 1

`\displaystyle I = (u)/(R) \Rightarrow R = (u)/(I) = (9 \ V)/(0.45 \ A) = 20 \ \Omega. \\ewline P = (\Delta uq)/(\Delta t) = Iu = 0.45 \ A \cdot 9 \ V = 4.05 \ (J)/(s) = 14580 \ (J)/(h) = 14.58 \ (kJ)/(h).`