Question

A 10-g mass of krypton occupies 15.0 l at a pressure of 210 kpa what is the volume of the krypton when the pressure is increased to 790 kpa

Answer 1

To solve this problem, use the combined gas law equation to find the final volume when the pressure is increased.

Step-by-step explanation:

To solve this problem, we can use the combined gas law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume. Given that the initial pressure is 210 kPa and the initial volume is 15.0 L, and the final pressure is 790 kPa, the final volume (V₂) can be calculated using the formula:
V₁P₁ = V₂P₂
Substituting the given values:
15.0 L * 210 kPa = V₂ * 790 kPa
Rearranging the equation to solve for V₂:
V₂ = (15.0 L * 210 kPa) / 790 kPa
V₂ ≈ 4.01 L

Answer 2

According to Boyle's Law," the volume of a fixed mass of gas is inversely proportional to the pressure applied on it".

Mathematically,
P₁ V₁ = P₂ V₂ -------- (1)

Data Given:
Initial Volume = V₁ = 15.0 L

Initial Pressure = P₁ = 210 kPa

Final Pressure = P₂ = 790 kPa

Final Volume = V₂ = ?

Solving eq. 1 for V₂,

V₂ = P₁ V₁ / P₂

Putting Values,
V₂ = (210 kPa × 15.0 L) ÷ 790 kPa

V₂ = 3.98 L