To rewrite this expression we can use the sum of cubes identity:

. Notice that we can express 8 as a cube:

, so we can rewrite our first term as

. Since our second term does not have a exact cubic root, we must rewrite as
![\sqrt[3]{243} ^(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ogdgyed24h6w9ji654kcv87hw5z4aj8tjy.png)
. Now we have

and
![b= \sqrt[3]{243}](https://img.qammunity.org/2019/formulas/mathematics/high-school/9f35mkh5vvqsttqpyjj53zqae690qmw7u4.png)
, so lets use the sum of cube identity to rewrite our expression:

![(2x)^3+ \sqrt[3]{243} ^3=(2x+ \sqrt[3]{243} )((2x)^2-2x \sqrt[3]{243} + \sqrt[3]{243} ^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/o8vxxjbdht7npbzdqury3dtj4c63tzcjph.png)
![(2x)^3+ \sqrt[3]{243} ^3=(2x+ 3\sqrt[3]{3^2} )((4x^2-6x \sqrt[3]{3^2} +27 \sqrt[3]{3} )](https://img.qammunity.org/2019/formulas/mathematics/high-school/s0n8ncr3rl3jowmh6kif40hstjqkquqa32.png)
![(2x)^3+ \sqrt[3]{243} ^3=(2x+ 3\sqrt[3]{9} )((4x^2-6x \sqrt[3]{9} +27 \sqrt[3]{3} )](https://img.qammunity.org/2019/formulas/mathematics/high-school/y8i9i8fs9t3wezdmu8ss3kg4uujp36v3gd.png)
We can conclude that we can use the sum of cubes identity to rewrite the expression
8x^3+243 as
![(2x+ 3\sqrt[3]{9} )((4x^2-6x \sqrt[3]{9} +27 \sqrt[3]{3} )](https://img.qammunity.org/2019/formulas/mathematics/high-school/sbkcy3srmc0drbfgs7bxmn6xwic23frqtv.png)