Question

Use properties of logarithms to expand logy/z^9

Answer 1

`\bf \textit{Logarithm of rationals} \\\\ log_a\left( (x)/(y)\right)\implies log_a(x)-log_a(y) \\\\\\ \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\ -------------------------------\\\\ log\left( (y)/(z^9) \right)\implies log(y)-log(z^9)\implies log(y)=9log(z)`