Question

The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs. This situation can be represented by a system of two linear equations. One of these equations is given. Write the second equation in the box.

d/3=h

Answer 1

What type of math is this problem? Is it advanced?

Answer 2

The required equation is
`d+h=120`

Explanation:

Given : The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs.

To find : Second equation from the situation?

Solution :

We have given,

'h' represent the humans,

'd' represent the dogs.

There must be 1 human to every 3 dogs.

So, One equation is
`(d)/(3)=h` (given)

According to question,

There can only be 120 dogs and humans combined.

i.e. The required equation is
`d+h=120`

Therefore, The event space imposes two restrictions on the party are

Equation 1 -
`(d)/(3)=h`

Equation 2 -
`d+h=120`