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How do I solve this problem? A restaurant is at 75% capacity with 120 patrons. How many people are in the restaurant when it is at 100% capacity?
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4 votes
How do I solve this problem?

A restaurant is at 75% capacity with 120 patrons. How many people are in the restaurant when it is at 100% capacity?

User Sudhir
by
7.6k points

2 Answers

4 votes
120 ---- 75%
x-----100%

x=120*100/75=160

or par/whole= 0.75
whole=120/0.75=160
User Amree
by
7.7k points
5 votes
Easy. We use PROPORTIONS!!

(120)/(x) = (75)/(100)
Now we cross multiply
120*100 = 75*x
Simplify
12000 = 75x
And get our trusty calculator out to solve.
The calculator says the answer is 160.
The restaurant can seat up to 160 people
User Laufwunder
by
7.6k points
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