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What is the ph of a buffer solution that is 0.45 m acetic acid (hc2h3o2) and 0.85 m sodium acetate (nac2h3o2)?

User Jblocksom
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1 Answer

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According to Henderson–Hasselbalch Equation,

pH = pKa + log [CH₃COO⁻] / [CH₃COOH]
As,
Ka of Acetic Acid = 1.8 × 10⁻⁵

pKa = -log Ka
pKa = -log 1.8 × 10⁻⁵
pKa = 4.74
So,
pH = 4.74 + log [0.85] / [0.45]

pH = 4.74 + log 1.88

pH = 4.74 + 0.276

pH = 5.01
User Gdt
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