we know that
If each dimension is scaled by a factor x, then the area of each side, and thus the surface area, is scaled by x² and the volume is scaled by x³.
Thus,
Part a) if the length, width, and height are reduced to half their original sizes, the area of each side is scaled by a factor of
(1/2)²------> 1/4
and
the volume is scaled by a factor of
(1/2)³-----> 1/8.
Thus,
if the initial surface area is 360 m²,
the final surface area is (1/4)(360 m²) = 90 m².
If the initial volume is 60 m³,
then
the final volume is (1/8)(60 m³) = 7.5 m³.
Part B_ If the length, width, and height are tripled, the area of each side is scaled by a factor of
(3)²-----> 9
and
the volume is scaled by a factor of
(3)³-------> 27.
Thus,
if the initial surface area is 360 m²,
the final surface area is (9)(360 m^2) = 3240 m².
If the initial volume is 60 m³,
then
the final volume is (27)(60 m^3) = 1620 m³.