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Find the equation of a line that passes through (5,-3) and is perpendicular to y = x. a) y = x + 2 b) y = x - 8 c) y = -x + 2 d) y = -x - 8
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Jul 2, 2019
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Find the equation of a line that passes through (5,-3) and is perpendicular to y = x.
a) y = x + 2
b) y = x - 8
c) y = -x + 2
d) y = -x - 8
Mathematics
high-school
Mboldt
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We know the slope is -1, because perpendicular line's slopes are always the negative reciprocal. We plug (5, -3) in to get:
-3 = -5 + b
b = 2
So we get C. y = -x + 2.
---
Hope this helps!
==jding713==
Prags
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Jul 6, 2019
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