Question

Does anyone know what the answer is
Thanks luvs xx

Answer 1

11 students like both English and maths but only 2 students like English but not maths
Reason:
n(u)= n(M) + n(E) +n(M union compliment E) - n(M intersect E)
26= 15+13+9-x
x=37-26
x=11 (which is the number of student who like both English and maths
Now,
The number of students who like English but not maths is
n(E) - x
=13-11
=2

Answer 2

We can use the multiplication rule to find the probability of both events happening .Therefore, the probability that a student chosen at random likes English but not Maths is 15/ 52.

In a class of 26 students, 15 of them like Maths, 13 of them like English, and 9 of them don't like Maths or English. To find the probability that a student chosen at random likes English but not Maths, we can use the Venn diagram provided.

The Venn diagram shows that there are 15 students who like Maths, 13 who like English, and 9 who don't like either. Since the probability of event A happening, and the probability of event B not happening, are independent, we can use the multiplication rule to find the probability of both events happening.

P(A and B) = P(A) * P(B-not)

P(A and B) = (15 / 26) * (13 / 26)

P(A and B) = 195 / 676

P(A and B) ≈ 0.29

Therefore, the probability that a student chosen at random likes English but not Maths is approximately 29%.