Question

For (x) =2x+1 and g(x)= x^2-7, find ( f o g ) (2)

Answer 1

f(x)=2x+1
g(x)= x²-7,
f o g(x)=2(x²-7)+1=2x²-14+1=2x²-13
f o g(2)=2*2²-13=8-13=-5

or
g(2)=4-7=-3
f o g(2)=2*(-3)+1=-5

Answer 2

-5

Explanation:

Given functions,

`f(x) =2x+1-----(1)`

`g(x)= x^2-7-----(2)`

`fog(x)=f(g(x))`

`=f(x^2-7)` ( From equation (2) )

`=2(x^2-7)+1` ( From equation (1) )

`=2x^2-14+1`

`=2x^2-13`

Hence,

`fog(2) = 2(2)^2-13=8-13=-5`