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What is the [oh–] in a sample of lime juice with a ph of 2.0?
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What is the [oh–] in a sample of lime juice with a ph of 2.0?

User Somdow
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1 Answer

5 votes
As we know,
pH + pOH = 14
Finding pOH,
pH + pOH = 14

2 + pOH = 14

pOH = 14 -12

pOH = 12

Concentration of [OH⁻] is calculate as,

pOH = -log [OH⁻]

12 = -log [OH⁻]

-12 = log [OH⁻]

[OH⁻] = 10⁻¹² Taking antilog

[OH⁻] = 1 × 10⁻¹²
User Milan M
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