Question

What is the solubility product expression for mercury(i) iodide, hg2i2?

Answer 1

Answer : The solubility product expression is,

`K_(sp)=[Hg^+]^2[I^-]^2`

Explanation :

Solubility product constant : It is defined as the product of the concentration of the ions present in a solution raised to the power by its stoichiometric coefficient in a solution of a salt. This takes place at equilibrium only. The solubility product constant is represented as,
`K__(sp)`.

The dissociation of mercury(i) iodide is written as:

`Hg_2I_2\rightleftharpoons 2Hg^++2I^-`

The expression for solubility constant for this reaction will be,

`K_(sp)=[Hg^+]^2[I^-]^2`

Therefore, the solubility product expression is
`K_(sp)=[Hg^+]^2[I^-]^2`

Answer 2

The solubility product expression for mercury (i) iodide Hg2 i2

write the equation for dissociation of Hg2i2 in water

that is Hg2i2 ---.> Hg2^2+ + 2 i ^-


therefore the solubility product is expressed as follows (Hg2^2+) (I-)^2

I- is squared since there is two iodine ions in the equation