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A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

User Radiaph
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2 Answers

2 votes

Answer:

C

Step-by-step explanation:

:)

User Fanhk
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With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

If
80% --- 50000 J
100% --- ?? J

Solution:
Input work = (100/80)*500000 J = 62500 J
User Baub
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