Question

Susan makes a simple pendulum by attaching a rock to a piece of string that is 24.6 centimeters long. Then she swings it back and forth. What is the period of her simple pendulum?

Answer 1

The equation for period is T (period)=2
`\pi`
`\sqrt{ (L (length of string))/(g (gravity))`. Pluging in the length of the string in meters, .246, and 9.8 for gravity you come to the answer of 0.995 or about 1 second.

Answer 2

0.99 s

Step-by-step explanation:

The period of a simple pendulum is given by:

`T=2 \pi \sqrt{(L)/(g)}`

where

L is the length of the pendulum

g is the acceleration due to gravity

In this problem, we have

`L=24.6 cm=0.246 m`

`g=9.81 m/s^2`

Substituting into the equation, we find the period:

`T=2 \pi \sqrt{(0.246 m)/(9.81 m/s^2)}=0.99 s`