Right equation of the line that passes through (-1,5) and has a slope of 3 in point slope form. A- x+1=3(y-5) B- x-5=3(y+1) C- y-5= 3(x+1) D- y+1 =3(x-5)

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asked Nov 28, 2019 147k views

5 votes

Right equation of the line that passes through (-1,5) and has a slope of 3 in point slope form.

A- x+1=3(y-5)
B- x-5=3(y+1)
C- y-5= 3(x+1)
D- y+1 =3(x-5)

Mathematics
high-school

TBB asked

by TBB

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1 Answer

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$\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -1 &,& 5~) \end{array} \\\\\\ % slope = m slope = m\implies 3 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=3[x-(-1)] \implies y-5=3(x+1)$

Keith Pickering answered Dec 3, 2019