Question

A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 5 more feet.

Answer 1

First we will find the total measure of the second base.

Second base is extended more so that meas it will measure extended part plus the first base.

Second base = 7 + 5 = 12.

Now for the area.

A = 1/2(b1+b2)(h)
A = 1/2(7 + 12)(7)
A = 66.5

The area is 66.5 ft²

Hope this helps :)

Answer 2

The area of the doghouse is
`66.5\ ft^(2)`

Explanation:

we know that

The area of trapezoid is equal to

`A=(1)/(2)(b1+b2)h`

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

`b1=7\ ft`

`b2=7+5=12\ ft`

`h=7\ ft`

substitute

`A=(1)/(2)(7+12)7=66.5\ ft^(2)`