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5 votes
Triangle ABC is a right triangle. if AC =7 and BC= 8 find AB. Leave your answer in simplest radical form.

A :

√(19)
B :

√(21)
C :

√(15)
D :

√(17)

User Primit
by
6.3k points

1 Answer

0 votes
Use the Pythagorean Theorem:
a^2+b^2=c^2 where a and b are the legs of the right triangle, and c is the hypotenuse (longest side!).

There is no picture provided with the problem, so it might be possible for the right angle to be at C and the hypotenuse is AB. But that won't work with the answer choices given, because then
(AB)^2=7^2+8^2 \\ (AB)^2=49+64=113 \\ AB = √(113)

Now you know that the 7 must be a leg and 8 the hypotenuse. Then
7^2+(AB)^2=8^2 \\ 49+(AB)^2=64 \\(AB)^2=64-49 \\ AB=√(15).

By the way, it cannot be that 7 is the hypotenuse because it's the longest side and 8 is longer.
User Will Nasby
by
6.0k points
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