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Write z = 2(cos(5pi/6) + i sin(5pi/6)) in rectangular form.

2 Answers

1 vote
answer is ( root 3 +i )
Write z = 2(cos(5pi/6) + i sin(5pi/6)) in rectangular form.-example-1
User Matt Carrier
by
6.2k points
2 votes

Answer:

z = (-√3 + i)

Explanation:

We have to write
z=2[cos((5\pi )/(6))+isin((5\pi )/(6))] in the rectangular form.

We will simplify this equation


z=2[cos((5\pi )/(6))+isin((5\pi )/(6))]

Since
cos((5\pi )/(6))=-(√(3) )/(2)

and
sin((5\pi )/(6))=(1)/(2)

Now we put the values in the equation


z=2[-(√(3) )/(2) +i((1)/(2)) ]

z = (-√3 + i)

Therefore the answer is z = -√3 + i

User Ithar
by
6.4k points
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