Question

A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped. Find the magnitude of force exerted on the running back during the collision.

Answer 1

The answer is 1600N by adding all the numbers up.

Hope this helps.

Answer 2

1000 N

Step-by-step explanation:

First, we need to find the deceleration of the running back, which is given by:

`a=(v-u)/(t)`

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

`a=(0-5 m/s)/(0.5 s)=-10 m/s^2`

And now we can calculate the force exerted on the running back, by using Newton's second law:

`F=ma=(100 kg)(-10 m/s^2)=-1000 N`

so, the magnitude of the force is 1000 N.