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How many mL of a 4.50M NaBr solution are needed to make 250 mL of a 0.75M solution of NaBr?
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How many mL of a 4.50M NaBr solution are needed to make 250 mL of a 0.75M solution of NaBr?

User Yansong
by
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1 Answer

4 votes
M1V1=M2V2

(4.50)(x)=(0.75)(250)
(4.50)(x)=187.5
x=41.67 mL
You might want to double check the formula used, but as a chem student I’m confident this is right
User Senne Verhaegen
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