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A jar contains 6 yellow and 8 blue gumballs. two gumballs will be drawn at random without being replaced. if the first gumball drawn is blue, what is the probability that the second gumball will also be
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A jar contains 6 yellow and 8 blue gumballs. two gumballs will be drawn at random without being replaced. if the first gumball drawn is blue, what is the probability that the second gumball will also be blue? leave answer as fraction

User Rob Paller
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1 Answer

3 votes
Yellow gumballs = 6
Blue gumballs = 8

P(Blue gumball) = 8/14 = 4/7

After first draw,
Yellow gumballs = 6
Blue gumballs = 7

Total=6+7 = 13 gumballs.
Second draw

P(Blue gumball) = 7/13

Probability of drawing two blue gumballs = 4/7*7*13 = 4/13
User Oswaldo Alvarez
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