Question

How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2)? express your answer to three significant figures and include the appropriate units?

Answer 1

Balance Chemical equation is,

P₄ + 10 Cl₂ → 4 PCl₅

According to Balance Equation,

123.89 g (1 mole) of P₄ reacts to produce = 4 Moles of PCl₅
Then,
23 g of P₄ will react with excess Cl₂ to produce = X moles of PCl₅

Solving for X,
X = (4 mol × 23 g) ÷ 123.89 g

X = 0.742 g of PCl₅
Result:
When 23 g of P₄ is reacted with excess Cl₂, 0.742 g of PCl₅ is produced.