Question

Consider the graph that represents the following quadratic equation y=-1/3(x+2)^2+5

Answer 1

Explanation:

Leading coefficient is negative

Hence the parabola is open downward.

Vertex of the graph = (-2,5)

Axis of symmetry is x +2 =0

x=-2

Answer 2

"downward" is correct.

Matching
(-1/3)(x +2)² +5
to
a(x -h)² +k
we find h = -2, k = 5.

The vertex is (h, k) = (-2, 5).