Question

What is the escape velocity from a red giant with a mass of 1msun and a radius of 150 rsun ?

Answer 1

The escape velocity from a red giant with a mass of 1Msun and a radius of 150Rsun is approximately 11 km/s or 25,000 mph.

Step-by-step explanation:

The escape velocity from a red giant with a mass of 1MSun and a radius of 150RSun can be calculated using the formula:

Vesc = ÝA(2GM/r)

where Vesc is the escape velocity, G is the gravitational constant (6.67 x 10-11 N m²/kg²), M is the mass of the red giant, and r is the radius of the red giant.

Substituting the given values, we have:

Vesc = ÝA(2(6.67 x 10-11 N m²/kg²)(1MSun)/(150RSun))

Simplifying the equation gives us the escape velocity:

Vesc ≈ 11 km/s or 25,000 mph.

Answer 2

We know:

Formula for escape velocity is:

V = √(2GM/R)

where,
G = Universal gravitational Constant = 6.67 * 10^(-11) Nm^2/Kg^2
M = Mass
R = Radius

So, we get, using given values:

Given:
m= 1 * mass of Sun = 1.9891*10^30 kg
R = 150 * Radius of Sun = 695500km

v = √(2*6.67*10^(-11) * 1.9891*10^30kg/695500000m)
so, v = 617671.632719m/s