187k views
1 vote
If be=6y+2 and ce=4y+6, find y

1 Answer

2 votes
The complete question is:
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y

Answer:
y = 2

Step-by-step explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC

From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2

Hope this helps :)

If be=6y+2 and ce=4y+6, find y-example-1
User Omarzouk
by
9.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories