The first thing we are going to to is checking if the sequence is arithmetic of geometric. A sequence is arithmetic if it has a common difference,

. A sequence is geometric if it has a common ratio,

.
Lets test for a common difference first. To do that we are going to subtract the current term from the previous term:



Since we have a common difference,

, or sequence is arithmetic.
Now, to find its 105 term, we are going to find its explicit formula using the general form of an arithmetic sequence:

where

is the nth term

is the first term

is the position of the term in the sequence

is the common diference
We can infer for our sequence that

, and for previews calculations we know that

. So lets replace those values:




Finally, to find the 105th term of the sequence, we just need to replace

with 105 in our explicit formula:



We can conclude that the 105th term of the sequence is -395.