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What is the 105th term of the sequence:

21, 17, 13, 9

1 Answer

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The first thing we are going to to is checking if the sequence is arithmetic of geometric. A sequence is arithmetic if it has a common difference,
d. A sequence is geometric if it has a common ratio,
r.
Lets test for a common difference first. To do that we are going to subtract the current term from the previous term:

9-13=-4

13-17=-4

17-21=-4
Since we have a common difference,
d=-4, or sequence is arithmetic.
Now, to find its 105 term, we are going to find its explicit formula using the general form of an arithmetic sequence:
a_(n)=a_(1)+(n-1)d
where

a_(n) is the nth term

a_(1) is the first term

n is the position of the term in the sequence

d is the common diference
We can infer for our sequence that
a_(1)=21, and for previews calculations we know that
d=-4. So lets replace those values:

a_(n)=a_(1)+(n-1)d

a_(n)=21+(n-1)(-4)

a_(n)=21-4n+4

a_(n)=25-4n
Finally, to find the 105th term of the sequence, we just need to replace
n with 105 in our explicit formula:

a_(n)=25-4n

a_(105)=25-4(105)

a_(105)=25-420

a_(105))=-395

We can conclude that the 105th term of the sequence is -395.
User Mike Williams
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