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DIVIDE please and thank you

DIVIDE please and thank you-example-1

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we have that
[(x²+2x+1)/(x-2)]/[(x²-1)/(x²-4)]

we know that
(x²+2x+1)---------> (x+1)²
(x²-1)------> (x+1)*(x-1)
(x²-4)----->(x+2)*(x-2)
so

[(x+1)²/(x-2)]/[(x+1)*(x-1)/(x+2)*(x-2)]
[(x+1)²*(x+2)*(x-2)]/[(x-2)*(x+1)/(x-1)]
[(x+1)*(x+2)]/[(x-2)*(x-1)]

the answer is
[(x+1)*(x+2)]/[(x-2)*(x-1)]



User Martin Gottweis
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