Question

A 969 n sky diver has opened his parachute to slow his descent to a constant speed the parachute applies 1,323 n of force. what deceleration does he experiences

Answer 1

See below

Step-by-step explanation:

Find mass of skydiver

F = mg

969 = m ( 9.81) so m = 98.8 kg

NET deccel force = 1323-969 = 354 N

F=ma

354 = 98.8 (a) = 3.58 m/s^2 decceleration