Question

a can contains 200 mixed nuts: almonds,cashew and peanuts. If the probability of choosing an almond is 1/10 and the probability of choosing a cashew is 1/4, how many peanut are in the can?

Answer 1

`(1)/(10) *200=20 \text{ almonds}\\ewline \\ewline (1)/(4) *200=50 \text{ cashews} \\ewline \\ewline 200-20-50=130 \text{ peanuts}`

Answer 2

1/10 of 200 is 20
1/4 of 200 is 50
20+50=70
200-70=130 peanuts