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29 votes
29 votes
A ball is thrown upwards at 24.39 m/s. What is the maximum height the ball reaches?

User Vorobey
by
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1 Answer

26 votes
26 votes

Answer:

30.3 m

Step-by-step explanation:

vf = final velocity = 0 at the apex

vo = original velocity = 24.39 m/s

a = - 9.81 m/s^2

vf = vo + at

0 = 24.39 -9.81 t shows t= 2.486 s

df = final height

df = vo t + 1/2 a t^2

= 24.39( 2.486) + 1/2 ( -9.81)(2.486^2) = 30.3 m

User Herr Kater
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3.2k points