Question

Which shows the following expression after the negative exponents have been eliminated

m^7 n^3/mn^-1,m=0,n=0

A.m^7 n^3 n/m

B.m^7 n^3 mn

C.m^7 n^3/m(-n)

D.m n /m^7 n

Answer 1

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Answer 2

A) (m^7 n^3 n) / m

Explanation:

Given:
`(m^7 n^3)/(m n^-1)`

Here we have to use exponent rule.

a^-1 = 1/a

So n^-1 = 1/n

Therefore,
`(m^7 n^3)/(m . (1)/(n) )`

If we have fraction in the denominator, we can flip and multiply, so we get

= (m^7 n^3 n) / m

Answer is A) (m^7 n^3 n) / m

Hope this will helpful.

Thank you.