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a violinist plays a note with a wavelength of 0.77955 m. if the speed of the sound is 343 m/s, what pitch is this note?

1 Answer

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Answer: The pitch of the note is: 439.99 Hz


Step-by-step explanation:

Since,

v = fλ

Therefore,

f = (v)/(\lambda)

Where v = 343m/s
λ = 0.77955 m

Plug-in the values:


f = (343)/(0.77955)

f = 439.99 Hz(pitch)
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