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Which number is a constant in the algebraic expression -x^2-6y+13x+7

User Sotona
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2 Answers

6 votes
Let's take a close look at x^2-6y+13x+7. Add the coefficient '1' in front of the first term: 1x^2-6y+13x+7.

The numerals {1, -6} are called "coefficients."
The final numeral, 7, stands alone. This is the "constant."
User Astex
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4 votes
A constant is defined as a number without a variable attacted to it. SO in your problem, the answer would be 7
User MKP
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