Question

How many 20.0-g ice cubes are required to absorb 67.1 kj from a glass of water upon melting?

Answer 1

By using heat of fusion (6.02 kJ / mol) of water as a conversion factor to determine the moles of water then use molar mass (18.02 g/mol) of water as a conversion factor to determine the mass of water and finally use the mass of one ice cube as a conversion factor to determine the number of ice cubes that absorbs 67.1 kJ energy:
67.1 kJ *
`(1 mole H2O)/(6.02 kJ) * (18.02 g H2O)/(1 mol H2O) * (1 ice cube)/(20.0 g H2O) = 10 ice cubes`
So the correct answer is 10 ice cubes