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A basketball player has a 50% chance of making each free throw. what is the probability that the player makes exactly five out of eleven free throws?

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Free throw follows binomial distribution.
probability of making free throw = probability of success = 0.5 = p
probability of fail = 1-0.5 = 0.5 = q

Binomial distribution is given by,
P(X) =
^nC_(x) p^(x) q^(n-x)

where n=11, x=5
Therefore,
P(X=5) =
^(11)C_(5) (0.5)^(5) (0.5)^(11-5) = 0.2255
User Roboli
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