Question

A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atmosphere. If the balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atmospheres. What is the volume of the balloon?

Answer 1

P1V1=P2V2 Boyle's law
0.97atm × 3.1L= 0.61atm × V2
V2= 4.9L

Answer 2

The volume of the balloon is 4.92 L at the height of 4 km.

Step-by-step explanation:

Initial Volume of the helium gas
`V_1= 3.1 L`

Initial pressure of the helium gas
`P_1= 0.97 atm`

Final volume of the helium gas =
`V_2`

Final pressure of the helium gas =
`P_2=0.61 atm`

Applying Boyle's law:

`P_1V_1=P_2V_2` (At constant temperature)

`V_2=(P_1* V_1)/(P_2)=(0.97 atm* 3.1 L)/(0.61 L)`

`V_2=4.92 L`

The volume of the balloon is 4.92 L at the height of 4 km.