A fragpole is 10 feet tall. It’s shadow is 12 feet long. How far is it from the lip of the fragpole to the end of its shadow?

asked Apr 22, 2019 216k views

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2 votes

pythagoras -> c^2 = a^2 + b^2

C^2 = 10^2 + 12^2
C^2 = 100 + 144
c= root square of 244
C= 15.62 feet

Stpoa answered Apr 22, 2019

by Stpoa

8.3k points

2 votes

Judging how the question is asked, I believe the answer is... 2 feet maybe?

Hope this helps

Esterlinkof answered Apr 27, 2019

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