for 1a,
set x=0 to find y-intercept.
set y=0 to find x-intercept.
the function is a positive parabola and is shown in the first image.
for 1b,
same process, similar looking graph shown in the second image.
for 2,



for 3, (refer to third image)
we'll use Pythagorean theorem


simplify and put it into a standard form:

quadratic equation:

then solve for x:

so one leg is 3cm
the other is two times that (6cm)