Question

How many moles are equal to 13.25 grams of barium permanganate

Answer 1

The molas mass of Ba(MnO4)2 is 375.21 g/m
So what’s next it’s a simple stoichiometry conversion:)
We start with what’s given: 13.25 g and because we want to convert to moles moles will be on top and grams on the bottom. We will end up dividing 13.25 by 375.21; this gives us 0.0353 mol Ba(MnO4)2

Answer 2

Answer: The number of moles of given mass of barium permanganate is 0.035 moles.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Given mass of barium permanganate = 13.25 g

Molar mass of barium permanganate = 375.2 g/mol

Putting values in above equation, we get:

`\text{Moles of barium permanganate}=(13.25g)/(375.2g/mol)=0.035mol`

Hence, the number of moles of given mass of barium permanganate is 0.035 moles.