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Davor Cubranic · Answer 1 · 2019-03-24T07:24:59+0000

well, we know the slope-intercept is y=5x-3 , now
$\bf y=\stackrel{slope}{5}x\stackrel{y-intercept}{-3}$ .

reason why is called the slope-intercept form, so, the slope is 5, and we know the line runs through -2,-13, thus

$\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -2 &,& -13~) \end{array} \\\\\\ % slope = m slope = m\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-13)=5[x-(-2)] \\\\\\ y+13=5(x+2)$

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