Question

How many moles of water are produced from 19.2 g of B2H6

from the reaction CH4 (g) + 2O2 (g)   CO2 (g) + 2H2O (l)

Answer 1

The Balanced chemical equation of reaction of Borane with oxygen is as follow,
B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,

`(27.66 g B2H6 produced)/(19.2 g of B2H6 will produce)` =
`(36 g of H2O)/(x g of water)`
Solving for x,
x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆

x = 24.98 g of H₂O

Result:
24.98 g of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.