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Part 1 of 2

Find the equation of the line that contains the point (-5,-3) and is perpendicular to the line x = 3.
Write the line in slope-intercept form, if possible. Graph the lines.
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Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answer. Use integers or fractions for any numbers in the equation.)
OA. The equation of the perpendicular line cannot be written in slope-intercept form. The
equation of the perpendicular line is
B. The equation of the perpendicular line in slope-intercept form is

User Ares
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1 Answer

18 votes
18 votes

Answer:

A line perpendicular to x=3 would be horizontal, with a slope of 0. y does not depend on x in a horizontal line: it is always the same value, regardless of x.

Explanation:

The equation for a straight line is y = mx + b, where m is the slope and b the y-intercept (the value of y when x=0). A line that is perpendicular to this line has a slope that is the negative inverse of m, which is -(1/m).

The line x=3 is a line that is perpendicular to the x axis. It has no slope and the b value is 0 (it does not cross the axis at x=0, since x is never 0. The equation is independent of y. It states that x is always 3, regardless of y.

This is plotted on the attached graph.

A perpendicular line has an undefined slope, since the Rise/Run of this line has a run of 0, for all values of y.

A line perpendicular to x=3 would be horizontal, with a slope of 0. y does not depend on x in a horizontal line: it is always the same value, regardless of x.

I can't make out the answer options. They appear to be cut off. Hopefully, the above information should guide one to the correct explanation.

Part 1 of 2 Find the equation of the line that contains the point (-5,-3) and is perpendicular-example-1
User Ricco
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