Question

if an aqueous solution containing M2+ ions electrolyzed by a current of 3.00 A for 60.0 min., resulting in 3.66 g of solid M produced at a cathode during this time, what is the likely identity of the element M

Answer 1

According to Faraday's Law,

W = I t e / F
Where,
W = Amount deposited = 3.66 g
I = Current = 3 A
t = Time = 60 min = 3600 s
e = Chemical equivalence
F = Faraday's Constant = 96500
Solving for e,
e = F W / I t
Putting Values,
e = (96500×3.66) ÷ (3 × 3600)
e = 32.7
As we know,
e = M / 2
solving for M,
M = e × 2
Putting value of e,
M = 32.7 × 2

M = 65.4

M = Zinc