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How many moles of nitrogen gas are there in 16.8 L of this gas at STP?

1 Answer

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According to Avogadro's Law, same volume of any gas at standard temperature and pressure will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

n = moles = ?
V = Volume = 16.8 L

Solution:
As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

= ( 1 mole × 16.8 L) ÷ 22.4 L

= 0.75 moles

Result:
16.8 L of Nitrogen gas will contain 0.75 moles at standard temperature and pressure.
User Mickel
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