Question

A line passes through points (-4, -19) and (-6, 4). what is the equation of the line written in slope-intercept form?

Answer 1

The equation of the line written in slope-intercept form is:


`y = mx + b`
Where m is the slope and b is the y-intercept.
You find the slope using the formula:


`m = (yb - ya)/(xb - xa)`
Where point A coordinates' are (-4,-19) and point B (-6, 4).


`m = (4 + 19)/( - 6 + 4)`

`m = - (23)/(2)`
Now you find b (y-intercept) substituting in y=-23/2x+b the coordinates of point A or point B:
(I'll use point B coordinates')
y=-23/2x+b
4=-23/2×(-6)+b
4=46+b
b=-42
The equation of the line is y=-23/2x-42