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A cylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. Each ball in the container has a radius of 2.5 centimeters. Find the amount of space in the container that is not occupied by rubber balls. Round your answer to the nearest whole number.

User Aiuspaktyn
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3 votes

Answer:

The amount of space not occupied by the rubber balls is given by:

Volume=(volume of the container)-(volume of the rubber balls)

volume of the container is given by:

V=πr²h

V=π*(5/2)²(20)

V=392.70 cm³

Volume of each ball is:

V=4/3πr³

V=4/3π(2.5)³=65.45 cm³

volume of four balls

65.45×4=261.8 cm³

The volume of the container that is not occupied by the balls will be:

V=392.70-261.8

V=130.9 cm³

Thus, to the nearest whole number is 131 cm³. Hope this Helps!

Explanation:

User Vlad Grichina
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6 votes
The amount of space not occupied by the rubber balls is given by:
Volume=(volume of the container)-(volume of the rubber balls)
volume of the container is given by:
V=πr²h
V=π*(5/2)²(20)
V=392.70 cm³

Volume of each ball is:
V=4/3πr³
V=4/3π(2.5)³=65.45 cm³
volume of four balls
65.45×4=261.8 cm³

The volume of the container that is not occupied by the balls will be:
V=392.70-261.8
V=130.9 cm³
User Vectrobyte
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7.9k points