Final answer:
The period of a 4.12 m long pendulum is approximately 4.06 seconds, calculated using the formula T = 2π√(L/g) where L is the length and g is the acceleration due to gravity.
Step-by-step explanation:
The period of a simple pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity, which is approximately 9.81 m/s² on the surface of the Earth. For a 4.12 m long pendulum, the period can be calculated as follows:
T = 2π√(4.12 m / 9.81 m/s²)
Plugging the values into the formula gives:
T ≈ 2π√(0.4196 s²)
T ≈ 2π√(0.6478 s)
T ≈ 4.06 s
Therefore, the period of a 4.12 m long pendulum is approximately 4.06 seconds.