Question

How many moles of acetylene gas occupy a volume of 3.25 l at stp?

Answer 1

Answer: 0.145 mol C2H2.

Answer 2

0.1449 moles of acetylene gas occupy a volume of 3.25 l at STP .

Step-by-step explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of acetylene gas =
`1 atm` (at STP)

V = Volume of acetylene gas = 3.25 L

n = number of moles of acetylene gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K (at STP)

Putting values in above equation, we get:

`n=(PV)/(RT)=(1 atm* 3.25L)/(0.0821 atm L/mol K* 273.15 K)`

n = 0.1449 moles

0.1449 moles of acetylene gas occupy a volume of 3.25 l at STP .